优化周转模组异常时,把产品重新放回穴位

master
lhiven 2 years ago
parent 5399f2c988
commit 831fdc81e2

@ -228,9 +228,9 @@ namespace Rs.MotionPlat.Flow
}
else
{
//undealTasks = LoadAndUnloadTask.Instance.GetTurnoverToTestTasks(ETaskDealStatus.Undeal);
//TurnoverDumpFlow.Instance.Dump(ETrayType.Turnover, undealTasks.Select(t => t.FromIndex + 1).ToList());
//TurnoverDumpFlow.Instance.Wait();
undealTasks = LoadAndUnloadTask.Instance.GetTurnoverToTestTasks(ETaskDealStatus.Undeal);
TurnoverDumpFlow.Instance.Dump(ETrayType.Turnover, undealTasks.Select(t => t.FromIndex + 1).ToList());
TurnoverDumpFlow.Instance.Wait();
Step = ETurnoverFlowStep.;
}
}
@ -241,11 +241,6 @@ namespace Rs.MotionPlat.Flow
List<TurnoverTraySlot> untestSlots = TurnoverTrayManager.Instance.GetSlots(ETurnoverTraySlotType.WaitTest, ETurnoverTraySlotStatus.Have);
if (untestSlots != null && untestSlots.Count > 0)
{
undealTasks = LoadAndUnloadTask.Instance.GetTurnoverToTestTasks(ETaskDealStatus.Undeal);
if(TurnoverDumpFlow.Instance.Dump(ETrayType.Turnover, undealTasks.Select(t => t.FromIndex + 1).ToList()))
{
TurnoverDumpFlow.Instance.Wait();
}
bool exit = false;
while (!exit)
{

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